Asked by Olivia
The second side is 10 more than the third side and the first side is 6 less than the third side. What are the sides of the triangle if the perimeter is 64yd?
Answers
Answered by
Anonymous
Let the length of the third side be x
The second side will be 10x(10 times)
The third side is x-6(6 less)
64=x+10x+x-6
The second side will be 10x(10 times)
The third side is x-6(6 less)
64=x+10x+x-6
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.