Asked by help!
                find all the real and complex zeros of the polynomial P(x)=x^4 -2x^3 -2x^2-2x-3
            
            
        Answers
                    Answered by
            Steve
            
    you know that anything more complicated than a quadratic is tough, so look for low-hanging roots: ±1,±2,±3. A little synthetic division yields
P(x) = (x-3)(x+1)(x^2+1)
now it's easy.
    
P(x) = (x-3)(x+1)(x^2+1)
now it's easy.
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.