Asked by Harold
What are the real and complex solutions of the polynomial equation?
27x^3 + 125 = 0
I already got the real solution x = -5/3, I just need to figure out how to find the complex solution. Any help?
27x^3 + 125 = 0
I already got the real solution x = -5/3, I just need to figure out how to find the complex solution. Any help?
Answers
Answered by
Steve
you have the sum of two cubes, so it factors into
(3x+5)((3x)^2-(3x)(5)+5^2)
= (3x+5)(9x^2-15x+25)
It's easy to check that the quadratic has no real solutions. Just use the quadratic formula, learned long ago in Algebra I...
(3x+5)((3x)^2-(3x)(5)+5^2)
= (3x+5)(9x^2-15x+25)
It's easy to check that the quadratic has no real solutions. Just use the quadratic formula, learned long ago in Algebra I...
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