Asked by lex

When you add 0.567 g of sodium metal to an excess of hydrochloric acid, you find that 5890 J of heat are produced. What is the enthalpy of the reaction as written below?

2Na(s)+2HCl(aq)=2NaCl(aq)+H2(g)
Answered by bobpursley
figure the moles of sodium you used.

then
MolesNa/2 liberated 5890J

Hr= -5890J*2/molesYouUsed
Answered by DrBob222
5890 J x (2*23/0.567) = ?
Answered by lex
477848.3?
Answered by DrBob222
That's ok but you have too many significant figures in the answer.
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