Asked by Blake
50 L of your 0.05M sodium. chloride solution, what volume of 1.25M solution would be necessary?
Answers
Answered by
DrBob222
To do what?
Answered by
DrRebel
Solution Prep'n by Dilution of Lab Stock ...
(Molarity x Volume)concentrated soln = (Molarity x Volume)diluted soln
M(conc) = 1.25M
V(conc) = ? (= volume needed to dilute to 50 Liters.)
M(dild) = 0.05M
V(dild) = 50 L
[(1.25M)(X) = (0.05M)(50L)
(x) = [(0.05M)(50L)]/(1.25M) = 2.0 L.
Transfer 2.0L of the 1.25M concentrated solution into mixing vessel and dilute with solvent (water) up to, but not to exceed 50L total volume.
(Molarity x Volume)concentrated soln = (Molarity x Volume)diluted soln
M(conc) = 1.25M
V(conc) = ? (= volume needed to dilute to 50 Liters.)
M(dild) = 0.05M
V(dild) = 50 L
[(1.25M)(X) = (0.05M)(50L)
(x) = [(0.05M)(50L)]/(1.25M) = 2.0 L.
Transfer 2.0L of the 1.25M concentrated solution into mixing vessel and dilute with solvent (water) up to, but not to exceed 50L total volume.
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