Question
50 L of your 0.05M sodium. chloride solution, what volume of 1.25M solution would be necessary?
Answers
DrBob222
To do what?
DrRebel
Solution Prep'n by Dilution of Lab Stock ...
(Molarity x Volume)concentrated soln = (Molarity x Volume)diluted soln
M(conc) = 1.25M
V(conc) = ? (= volume needed to dilute to 50 Liters.)
M(dild) = 0.05M
V(dild) = 50 L
[(1.25M)(X) = (0.05M)(50L)
(x) = [(0.05M)(50L)]/(1.25M) = 2.0 L.
Transfer 2.0L of the 1.25M concentrated solution into mixing vessel and dilute with solvent (water) up to, but not to exceed 50L total volume.
(Molarity x Volume)concentrated soln = (Molarity x Volume)diluted soln
M(conc) = 1.25M
V(conc) = ? (= volume needed to dilute to 50 Liters.)
M(dild) = 0.05M
V(dild) = 50 L
[(1.25M)(X) = (0.05M)(50L)
(x) = [(0.05M)(50L)]/(1.25M) = 2.0 L.
Transfer 2.0L of the 1.25M concentrated solution into mixing vessel and dilute with solvent (water) up to, but not to exceed 50L total volume.