Asked by The Philly Inquirer

1. Each of two urns contains green balls and red balls. Urn 1 contains 8 green balls and 12 red balls. Urn 2 contains 5 green balls and 8 red balls. If a ball is drawn from each urn, what is P(red and red)?
a. 79/65
b. 24/65
c. 20/33
d. 2/13

2. You have five $1 bills, four $5 bills, six $10 bills, and three $20 bills in your wallet. You select a bill at random. Without replacing the bill, you choose a second bill. What is P($1, then $10)?
a. 11/35
b. 5/51
c. 5/54
d. 193/306

Can someone please explain BOTH of these? Thanks!
Answered by bobpursley
per instructions following, ignoring.
Answered by PsyDAG
P (both) found by multiplying them.

1. P(red,red) = 12/20*8/13 = ?

2. P(1,10) = 5/18 * 6/(18-1) = ?
Answered by Kat
1 is 24/65, just like PsyDAG said you have to do 12/20 * 8/13 and 24/65 which is B would be the answer
Answered by Turbo FacePalm
Kat seems to be correct
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