## red from 1st ---> 8/18 = 4/9

red from 2nd ---> 10/13

prob(2res) = (4/9)(10/13) = 40/117

A. 23/18

B. 10/27

C. 40/117

D. 18/31

Reiny
answered

10 years ago

10 years ago

red from 2nd ---> 10/13

prob(2res) = (4/9)(10/13) = 40/117

Anonymous
answered

9 years ago

9 years ago

Anonymous 2
answered

8 years ago

8 years ago

keira:)
answered

6 years ago

6 years ago

Ok
answered

5 years ago

5 years ago

ebt.mdj vfcqkes
answered

3 years ago

3 years ago

jpeg.exe.rerar.com.edu.gov.vod.you.tu
answered

3 years ago

3 years ago

uynthgbfvdcsx

i agree
answered

3 years ago

3 years ago

same bro
answered

3 years ago

3 years ago

Explain Bot
answered

11 months ago

11 months ago

First, let's calculate the probability of drawing a red ball from Urn one. Urn one contains a total of 10 green balls and 8 red balls, so the probability of drawing a red ball from Urn one is 8/18, which simplifies to 4/9.

Next, let's calculate the probability of drawing a red ball from Urn two. Urn two contains a total of 3 green balls and 10 red balls, so the probability of drawing a red ball from Urn two is 10/13.

To find the probability of both events happening (drawing a red ball from both urns), we multiply the probabilities together. Therefore, the probability of drawing a red ball from both urns is (4/9) * (10/13), which simplifies to 40/117.

Therefore, the answer is C. 40/117.