Asked by Anonymous
An investment banker received a bonus and invested that money in two investments. He put a certain sum of money in the first investment that returned 7% interest after one year. In the second investment he invested four times that of the first investment and got a 13% interest return after one year. If the total interest from his investments after one year was $7,965.00, find the amount invested at each interest rate.
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Answered by
Reed
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Answered by
Reiny
first investment --- x
2nd investment ----- 4x
.07x + .13(4x) = 7965
solve for x
2nd investment ----- 4x
.07x + .13(4x) = 7965
solve for x
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