I will do more than you asked because I am sure there are more parts
weight = m g = 1.6*9.81 = 15.7 N
friction force = .48*15.7 = 7.53 N
work done by friction = 7.53*.125
= .942 Joules
work done by spring = (1/2)(480)(.125^2)
= 3.75 J (ANSWER YOU ASKED FOR)
total work done by friction and spring = .942+3.75 = 4.69 Joules (LOL, what you said but that is total not spring(
so
(1/2) m v^2 = 4.69 before crash
A moving 1.60 kg block collides with a horizontal spring whose spring constant is 480 N/m.
The block compresses the spring a maximum distance of 12.50 cm from its rest position. The coefficient of kinetic friction between the block and the horizontal surface is 0.480.
What is the work done by the spring in bringing the block to rest?
I got 4.69J but it says its wrong. I sum up work done by friction plus work by spring
2 answers
I think there something wrong with the quiz, cuz it tells me its wrong. I tried 3.75N (work by spring) and also total work done. It shouldnt be, I got the 2 other questions right. Still, thank you.
4 answers