Asked by Anonymous
If a body projected vertically upwards, give a graph showing variation in its kinetic energy
Answers
Answered by
Damon
constant = kinetic E + potential E
= (1/2) m v^2 + m g h
but
v = Vi - g t
so v^2 = Vi^2 - 2 Vi g t - g^2 t^2
so
Ke = (1/2) m v^2
= .5m [ Vi^2 - 2 Vi g t - g^2 t^2]
which is a parabola with vertex at (.5 m v^2) and dropping off with time
= (1/2) m v^2 + m g h
but
v = Vi - g t
so v^2 = Vi^2 - 2 Vi g t - g^2 t^2
so
Ke = (1/2) m v^2
= .5m [ Vi^2 - 2 Vi g t - g^2 t^2]
which is a parabola with vertex at (.5 m v^2) and dropping off with time
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