totally unreasonable answer
some number squared has to be 7
so a quick mental check would be
(2(17) - 1)^2
= 33^2
= 1089 , certainly not 7
this is a standard quadratic, which is in a nice form
(2x-1)^2 = 7
2x-1 = ± √7
2x = 1 ± √7
x = (1 ± √7)/2
= appr 1.823 or x = appr -0.823
Ln(2x-1)^2=7 solve for x.
Please check my answer!!!
=17.0577259793
Is this number too big?
2 answers
Assuming you meant the log of (2x-1)^2, then that means
(2x-1)^2 = e^7
2x-1 = e^3.5 = 33.115
2x = 34.115
x = 17.0577
Looks ok to me.
of course, there is the other root using 2x-1 = -33.115
(2x-1)^2 = e^7
2x-1 = e^3.5 = 33.115
2x = 34.115
x = 17.0577
Looks ok to me.
of course, there is the other root using 2x-1 = -33.115
2 answers