Let x and y be real numbers. If (x+yi)-(2-3i)=-6+4i, what are the values of x and y?

Answer 1

So far I got
x+yi-2+3i=-6+4i
x+yi+3i=-6+2+4i
x+yi+3i=-4+4i
x+yi=-4+i

Answer 2

the real parts of the left side must match the real parts of the right side, and the imaginary parts ....

your steps are correct, so
x = -4, y = 1

Answer 3

Thanks