Asked by hello
Real numbers x and y have a difference of 16 and a product of 23. Find x^2+y^2.
Answers
Answered by
Reiny
larger --- x
smaller --- y
x-y = 16
xy = 23
x^2 + y^2 = (x - y)^2 + 2xy
= 16^2 + 46 = 302
smaller --- y
x-y = 16
xy = 23
x^2 + y^2 = (x - y)^2 + 2xy
= 16^2 + 46 = 302
Answered by
hi
reiny is correct
Answered by
hence, we are done.
x^2+y^2=(x-y)^2+2xy=16^2+2*23=256+46=302
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