Asked by Bryce
The following Chemical reaction produces a precipitate in an aqueous solution.
NaOH(aq)+Mg(Cl)2(aq)<->NaCl(aq)+Mg(OH)2(s)
With an equilibrium constant of K=1.3. If NaOH and Mg(Cl)2 are added in stoiciometric ratio and 1.20 mol of NaOH are present at Equilibrium, how much precipitate is produced (in moles)?
NaOH(aq)+Mg(Cl)2(aq)<->NaCl(aq)+Mg(OH)2(s)
With an equilibrium constant of K=1.3. If NaOH and Mg(Cl)2 are added in stoiciometric ratio and 1.20 mol of NaOH are present at Equilibrium, how much precipitate is produced (in moles)?
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