Asked by mo
a boat leaves the harbor and travels 11 mph toward a small island. 3 hours later, a cabin cruiser leaves the same harbor and travels 33 mph. how many hours after the cabin cruiser leaves the harbor will be next to the motorboat
Answers
Answered by
Reiny
let the time taken by the cabin cruiser to catch up to the boat be t hours
So 33t = 11(t+3)
33t = 11t + 33
22t = 33
t = 33/22 = 3/2
check:
the boat went for 3+3/2 or 4.5 hours
at 11 mph, went 49.5 miles
the cruiser went for 3/2 hours at
33 mph, went 49.5
looks like it caught up
My answer is correct
So 33t = 11(t+3)
33t = 11t + 33
22t = 33
t = 33/22 = 3/2
check:
the boat went for 3+3/2 or 4.5 hours
at 11 mph, went 49.5 miles
the cruiser went for 3/2 hours at
33 mph, went 49.5
looks like it caught up
My answer is correct
Answered by
mo
so the cabin cruiser caught up in 3/2 hours?
Answered by
Reiny
Yes, I think I had that.
Look at my definition of t
Look at my definition of t
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