Asked by Dorian

A spring has its right end fixed and is installed on a horizontal table so that the free end, at equilibrium, is at x=3.00m. A 1.65kg block coming from the left slides along the table. When it passes the origin, it is moving at 5.58m/s. It strikes the spring, compresses it momentarily, and is then sent back toward the left, where it eventually comes to rest at the point x=1.5m. The coefficient of kinetic friction between the block and the table is 0.300. By what distance was the spring compressed?

Answers

Answered by Chanz
The kicker is the energy lost to friction during compression and expansion which will be Ff(x) times 2.
So KE - 2Ff x - Ff(d) = 0
but Ff is mu mg
Note m is not really needed for the question.
Answered by Anonymous
.395
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