find P: P is halfway between a,b, so P=(-1,2) and likewise Q=(0,1)
line PQ:
Y-y1=m(x-x1) first find slope
m=1/-1=-1 (change in y/changeinx)
y-1=-1(x-0)
slope of BC: m=-2/2=-1 same slope, has to be parallel
Length PQ=sqrt( (-1)^2+1^2)=sqrt2
length BC= sqrt( (-4)^2+(4)^2)=2sqrt2 which is twice as long as PQ
A(0,1) B(-2,3) C(2,-1) are the vertices of a triangle ABC. P and Q are the midpoint of the side AB and AC.
(a) find the equation of PQ,
(b) show that PQ is parallel to BC.
(c) show the length PQ = 1/2 length BC.
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