Question
The line segment joining a vertex of a triangle and the midpoint of the opposite side is called the median of the triangle. Given a triangle whose vertices are A(4,-4), B(10, 4) and C(2, 6), find the point on each median that is two-thirds of the distance from the vertex to the midpoint of the opposite side.
Answers
Steve
Since all three medians meet there, finding where two intersect is enough.
AB has midpoint P at (5,0)
BC has midpoint Q at (6,5)
The lines CP and AQ are
y-6 = (0-6)/(5-2) (x-2)
y+4 = (5+4)/(6-4) (x-4)
Now just find where the two lines intersect.
AB has midpoint P at (5,0)
BC has midpoint Q at (6,5)
The lines CP and AQ are
y-6 = (0-6)/(5-2) (x-2)
y+4 = (5+4)/(6-4) (x-4)
Now just find where the two lines intersect.
Vaibhavi
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Vaibhavi
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Sakshi
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