Asked by Jacqueline

A paratrooper w/ a fully loaded pack has a mass of 120kg. The force due to air resistance on him when falling w/ an unopened parachute has magnitude
F(sub)d = bv^2, where b=0.14 N*s/m^2.

a) if he is falling w/ an unopened parachute at 64m/s, whats is the force of air resistance acting on him?

b) what is his acceleration?


c) what is his terminal velocity?

I figured that to be:
v(sub)t= sqrt (120 *9.8) / (0.14)


Can someone please help me find acceleration and the force of air resistance?

Thank you!! :)

Answers

Answered by drwls
a) Use the formula that was provided. The drag force is
F = b*(64)^2 = 573 N at v = 64 m/s

b) a = F/Mass

c) Let the terminal velocity be V. It occurs when bV^2 = M g. That is before the parachute opens.

V = sqrt (M g/b)
which is what you had

The value of b will increase by a large factor when the parachute opens, but the question is not concerned with that.

There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions