Asked by Nick
A man completes 31 lengths of a 50 metre pool with an average speed of 0.9 km/h. What is the magnitude of his average velocity vector in Standard SI units?
Answers
Answered by
Damon
Velovicy is a VECTOR
north one way, south back
31 lengths, 30 of which were back and forth
so
went 50 meters total north in the end
How long did it take?
31 * 50 = 1550 meters back and forth at 900 m/3600 s
time = 1550 *3600/900
= 6200 seconds
so 50 meters/6200 seconds
= 0.00806 m/s NORTH
north one way, south back
31 lengths, 30 of which were back and forth
so
went 50 meters total north in the end
How long did it take?
31 * 50 = 1550 meters back and forth at 900 m/3600 s
time = 1550 *3600/900
= 6200 seconds
so 50 meters/6200 seconds
= 0.00806 m/s NORTH
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