A man completes 31 lengths of a 50 metre pool with an average speed of 0.9 km/h. What is the magnitude of his average velocity vector in Standard SI units?

1 answer

Velovicy is a VECTOR

north one way, south back

31 lengths, 30 of which were back and forth
so
went 50 meters total north in the end

How long did it take?
31 * 50 = 1550 meters back and forth at 900 m/3600 s
time = 1550 *3600/900
= 6200 seconds

so 50 meters/6200 seconds

= 0.00806 m/s NORTH