Asked by Anonymous

A SUPERSONIC FIGHTER JET FLYING HORIZONTALLW AT HEIGHT OF 4KM ABOVE THE GROUND AND AT A SPEED OF 400M/S FIRES A ROCKET VERTICALLY DOWNWARD. THE ROCKET IS RELEASED WITH AN INITIAL SPEED OF 80M/S CALCULATE THE TIME OF FLIGHT OF THE ROCKET AND THE HORIZONTAL DISTANCE FROM THE POINT OF ITS RELEASE AT WHICH THE ROCKET LANDS

Answers

Answered by Chanz
No need to shout.
4000 = 80t + 4.9 t^2
You'll have to solve the quadratic
Horizontal will be 400t
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