Asked by Anonymous
A SUPERSONIC FIGHTER JET FLYING HORIZONTALLW AT HEIGHT OF 4KM ABOVE THE GROUND AND AT A SPEED OF 400M/S FIRES A ROCKET VERTICALLY DOWNWARD. THE ROCKET IS RELEASED WITH AN INITIAL SPEED OF 80M/S CALCULATE THE TIME OF FLIGHT OF THE ROCKET AND THE HORIZONTAL DISTANCE FROM THE POINT OF ITS RELEASE AT WHICH THE ROCKET LANDS
Answers
Answered by
Chanz
No need to shout.
4000 = 80t + 4.9 t^2
You'll have to solve the quadratic
Horizontal will be 400t
4000 = 80t + 4.9 t^2
You'll have to solve the quadratic
Horizontal will be 400t
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.