Question
A SUPERSONIC FIGHTER JET FLYING HORIZONTALLW AT HEIGHT OF 4KM ABOVE THE GROUND AND AT A SPEED OF 400M/S FIRES A ROCKET VERTICALLY DOWNWARD. THE ROCKET IS RELEASED WITH AN INITIAL SPEED OF 80M/S CALCULATE THE TIME OF FLIGHT OF THE ROCKET AND THE HORIZONTAL DISTANCE FROM THE POINT OF ITS RELEASE AT WHICH THE ROCKET LANDS
Answers
No need to shout.
4000 = 80t + 4.9 t^2
You'll have to solve the quadratic
Horizontal will be 400t
4000 = 80t + 4.9 t^2
You'll have to solve the quadratic
Horizontal will be 400t
Related Questions
A kite which is flying at a height of 215 m above the ground level descends at the rate of 5m per m...
a plane is flying horizontally at a height of 10000m above a level stretch of ground at a constant s...
The angle of elevation from Jet fighter. A ground on 60 degree after a flight takeoff 15 seconds the...
A CF-18 fighter jet flying at 350 m/ s engages its afterburners and accelerates at a rate of 12.6 m/...