Asked by Nikela
You dissolve 6g of Co(ClO4)2 (molar mass: 257.83) in 1 liter of water. Assuming the entire sample dissolves, how many individual perchlorate ions are present in this solution?
I'm so lost where to start.
I'm so lost where to start.
Answers
Answered by
Anonymous
uiuiuiuiuiuiuiuiuiuiyu
Answered by
DrBob222
Co(ClO4)2 ==> Co^2+ + 2ClO4^-
You know 1 mole of anything contains 6.02E23 molecules. So how many moles do you have of this stuff. mols = grams/molar mas so
mols = 6/257.83 = ?
So ? x 6.02E23 = number of molecules of Co(ClO4)2. You want to know ClO4^-. There are two of those for every 1 Co(ClO4)2 so there are twice as many of the ClO4^-.
You know 1 mole of anything contains 6.02E23 molecules. So how many moles do you have of this stuff. mols = grams/molar mas so
mols = 6/257.83 = ?
So ? x 6.02E23 = number of molecules of Co(ClO4)2. You want to know ClO4^-. There are two of those for every 1 Co(ClO4)2 so there are twice as many of the ClO4^-.
Answered by
Nikela
Okay so moles= .0233
0.0233*6.022*10^23=1.403*10^23
1.403*10^23*2=2.806*10^22
Did I get it?
0.0233*6.022*10^23=1.403*10^23
1.403*10^23*2=2.806*10^22
Did I get it?
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