Asked by mar
Soft tissue has a linear attenuation coefficient in the range of
μ = 0.35 cm−1
at 30 keV and
μ = 0.16 cm−1
at 100 keV. For this problem we use
μ = 0.21 cm−1,
which applies at around 50 keV incident X-ray energy.
(a) What fraction of X-ray photons at 50 keV are passing through a person's body? Hint: the person's body thickness is about 19 cm. Use a soft tissue approximation, i.e., neglecting bones.
(b) We compare bone and soft tissue of 4 cm thickness each. Using
μbone = 0.57 cm−1
at 50 keV, what fraction of a 50 keV incident X-ray beam is stopped in bone and soft tissue respectively?
μ = 0.35 cm−1
at 30 keV and
μ = 0.16 cm−1
at 100 keV. For this problem we use
μ = 0.21 cm−1,
which applies at around 50 keV incident X-ray energy.
(a) What fraction of X-ray photons at 50 keV are passing through a person's body? Hint: the person's body thickness is about 19 cm. Use a soft tissue approximation, i.e., neglecting bones.
(b) We compare bone and soft tissue of 4 cm thickness each. Using
μbone = 0.57 cm−1
at 50 keV, what fraction of a 50 keV incident X-ray beam is stopped in bone and soft tissue respectively?
Answers
Answered by
kk
khklvuy
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.