A ball is attached to a center post by a string that is 0.382 m long. The ball is moving in a circle on a frictionless table top at a speed of 1.28 m/s with a radius of 0.382 m. What is the centripetal acceleration of the ball?

asked by Em

9 years ago

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1 answer

a(c) = v²/R=
=(1.28)²/0.382 = 4.29 m²/s

answered by Anonymous

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Question

A ball is attached to a center post by a string that is 0.382 m long. The ball is moving in a circle on a frictionless table top at a speed of 1.28 m/s with a radius of 0.382 m. What is the centripetal acceleration of the ball?

1 answer

a(c) = v²/R=
=(1.28)²/0.382 = 4.29 m²/s

Anonymous · Answer

a(c) = v²/R= =(1.28)²/0.382 = 4.29 m²/s