Asked by Em
If the angular velocity, ω, changes from 7.07 rad/s to 24.2 rad/s over a time of 6.42 s, what is the angular acceleration, α?
Answers
Answered by
Anonymous
ω=ωₒ+εt
ε=( ω-ωₒ)/t=
=(24.2-7.07)/6.42 = 2.67 rad/s
ε=( ω-ωₒ)/t=
=(24.2-7.07)/6.42 = 2.67 rad/s
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