Asked by muskan
calculate the molarity of solution cacl2 . if on the chemical analysis . it is found that 200 ml of solution contains 3 into 10 raise the power 22 cl- ions
Answers
Answered by
DrBob222
You need to find the caps key and use it. 5E3 means 5 x 10^3 = 5000 = 5 times 10 to the third power.
1 mol contains 6.02E23 ions.
3E22/6.02E23 = approx 0.05 mol Cl^- ions.
mols CaCl2 = 1/2 that since 1 mol CaCl2 contains 2 mols CaCl2.
Then M = mols/L = approx 0.05 mols/0.200 L = ?
1 mol contains 6.02E23 ions.
3E22/6.02E23 = approx 0.05 mol Cl^- ions.
mols CaCl2 = 1/2 that since 1 mol CaCl2 contains 2 mols CaCl2.
Then M = mols/L = approx 0.05 mols/0.200 L = ?