Asked by Reed
A 25 g bullet with a muzzle velocity of 300 m/s is fired into a board 4.0 cm thick. A). In a hard board, the bullet penetrates 3.0 cm and comes to a stop. What is the average force exerted on the bullet by the board?
B). For a soft board, the bullet goes through the board and emerges with a speed of 50 m/s. What was the average force exerted on the bullet by the board.
Answers:
A= 37,500 N
B= 27344 N
Show work
B). For a soft board, the bullet goes through the board and emerges with a speed of 50 m/s. What was the average force exerted on the bullet by the board.
Answers:
A= 37,500 N
B= 27344 N
Show work
Answers
Answered by
Damon
momentum = m v = .025 * 300
stops in .03 meters
average speed during stop = 150 m/s
time to stop = .03 meters/150 m/s
force = change in momentum/time
= .025 * 300 / (.03/150)
= 37,500 N
do B the same way
stops in .03 meters
average speed during stop = 150 m/s
time to stop = .03 meters/150 m/s
force = change in momentum/time
= .025 * 300 / (.03/150)
= 37,500 N
do B the same way
Answered by
Reed
Maybe you should read the book to find out.
Answered by
Atheist Chad
Maybe we could just get rid of guns... ¯\_(ツ)_/¯
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