Asked by Anonymous

the temperature of 500g of a certain metal is raised to 100 degre celcius and it is then placed in 200g of water at 15 degre celcius.if the final steady temperature raises to 21 degre celcius,calculate the specific heat capacity of the metal
Answered by Chanz
mc(Tf-Ti) water + mc(Tf-Ti) metal = 0
the only unknown is the c of the metal (you can look up c for water)
Answered by Jack
125
Answered by toyin
how is it 125 plz
Answered by Habyarimana
I need the answer of this
The temperature of 500g of a certain metal is raised to 100degre celcius and it is then placed in 200g of water at 15 degre celcius .
If the final stead temperature is 21 degre celcius .find the specific heat capacity
Answered by anjay
mana jawapan adoi
Answered by Kaye Luchie E. Bongo
The Answer is 127 J/kg°C.
Answered by vickky
Explain coz I don't understand
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