Asked by Anonymous
the temperature of 500g of a certain metal is raised to 100 degre celcius and it is then placed in 200g of water at 15 degre celcius.if the final steady temperature raises to 21 degre celcius,calculate the specific heat capacity of the metal
Answers
Answered by
Chanz
mc(Tf-Ti) water + mc(Tf-Ti) metal = 0
the only unknown is the c of the metal (you can look up c for water)
the only unknown is the c of the metal (you can look up c for water)
Answered by
Jack
125
Answered by
toyin
how is it 125 plz
Answered by
Habyarimana
I need the answer of this
The temperature of 500g of a certain metal is raised to 100degre celcius and it is then placed in 200g of water at 15 degre celcius .
If the final stead temperature is 21 degre celcius .find the specific heat capacity
The temperature of 500g of a certain metal is raised to 100degre celcius and it is then placed in 200g of water at 15 degre celcius .
If the final stead temperature is 21 degre celcius .find the specific heat capacity
Answered by
anjay
mana jawapan adoi
Answered by
Kaye Luchie E. Bongo
The Answer is 127 J/kg°C.
Answered by
vickky
Explain coz I don't understand
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