Question
If we have 2.500g of CuCl2•2H2O and 2.200 g of Cu to make CuCl. What is the theoretical yield?
Answers
DrBob222
You need to confirm molar masses and all the calculations. My calculator is on the blink and I've just estimated the calculations and molar masses.
CuCl2*2H2O + Cu ==> 2CuCl + 2H2O
mols CuCl2*2H2O = grams/molar mass = 2.500/170 = 0.015
mols Cu = 2.200/63 = 0.035
How much CuCl can we get with CuCl2*2H2O? That's
0.015 mols CuCl2*2H2O x (2 mol CuCl/1 mol CuCl2*2H2O) = about 0.030
How much CuCl can we get with Cu? That's
0.035 x (2 mol CuCl/1 mol Cu) = 0.070
The limiting reagent is CuCl2*2H2O; therefore, we will get about 0.030 mols CuCl from CuCl2*2H2O. Then grams CuCl = mols CuCl x molar mass CuCl = ? and this is the theoretical yield.
CuCl2*2H2O + Cu ==> 2CuCl + 2H2O
mols CuCl2*2H2O = grams/molar mass = 2.500/170 = 0.015
mols Cu = 2.200/63 = 0.035
How much CuCl can we get with CuCl2*2H2O? That's
0.015 mols CuCl2*2H2O x (2 mol CuCl/1 mol CuCl2*2H2O) = about 0.030
How much CuCl can we get with Cu? That's
0.035 x (2 mol CuCl/1 mol Cu) = 0.070
The limiting reagent is CuCl2*2H2O; therefore, we will get about 0.030 mols CuCl from CuCl2*2H2O. Then grams CuCl = mols CuCl x molar mass CuCl = ? and this is the theoretical yield.