Asked by Amitabha

Andrew and Daniel recently took part in a marathon. After they had finished, they noticed
that Andrew finished ahead of twice as many runners as finished ahead of Daniel, and that Daniel finished ahead of 1.5 times as many runners as finished ahead of Andrew. Andrew finished in 21st
place. How many runners took part in the marathon?

Answers

Answered by Steve
20 ahead of andrew
30 behind daniel

Now we know that

30+1+x = 2x+1+20
10=x

So, there were 41 runners, in order:

30...Daniel...10
20...Andrew...20
Answered by Steve
or, better,

20..Andrew..9..Daniel..10
Answered by Mercy
A = 1 + 2x
Runners that finished ahead of Daniel is x
21 = 1 + 2x
21 - x = 2x
X = 10

Runners that finished ahead of Andrew is 20
D = 1.5 x 20
= 30 + 1
= 31
Total = 31 + 10
= 41
Answered by Queen
Let the many runners that finished ahead of Daniel be x
Andrew=1+2x
21=1+2x
21-1=2x
20=2x
x=10
Many runners ahead of Andrew are 20
Daniel =1+1.5×20
=1+30=31
Total = 31+10=
41
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions