Asked by Amitabha
Andrew and Daniel recently took part in a marathon. After they had finished, they noticed
that Andrew finished ahead of twice as many runners as finished ahead of Daniel, and that Daniel finished ahead of 1.5 times as many runners as finished ahead of Andrew. Andrew finished in 21st
place. How many runners took part in the marathon?
that Andrew finished ahead of twice as many runners as finished ahead of Daniel, and that Daniel finished ahead of 1.5 times as many runners as finished ahead of Andrew. Andrew finished in 21st
place. How many runners took part in the marathon?
Answers
Answered by
Steve
20 ahead of andrew
30 behind daniel
Now we know that
30+1+x = 2x+1+20
10=x
So, there were 41 runners, in order:
30...Daniel...10
20...Andrew...20
30 behind daniel
Now we know that
30+1+x = 2x+1+20
10=x
So, there were 41 runners, in order:
30...Daniel...10
20...Andrew...20
Answered by
Steve
or, better,
20..Andrew..9..Daniel..10
20..Andrew..9..Daniel..10
Answered by
Mercy
A = 1 + 2x
Runners that finished ahead of Daniel is x
21 = 1 + 2x
21 - x = 2x
X = 10
Runners that finished ahead of Andrew is 20
D = 1.5 x 20
= 30 + 1
= 31
Total = 31 + 10
= 41
Runners that finished ahead of Daniel is x
21 = 1 + 2x
21 - x = 2x
X = 10
Runners that finished ahead of Andrew is 20
D = 1.5 x 20
= 30 + 1
= 31
Total = 31 + 10
= 41
Answered by
Queen
Let the many runners that finished ahead of Daniel be x
Andrew=1+2x
21=1+2x
21-1=2x
20=2x
x=10
Many runners ahead of Andrew are 20
Daniel =1+1.5×20
=1+30=31
Total = 31+10=
41
Andrew=1+2x
21=1+2x
21-1=2x
20=2x
x=10
Many runners ahead of Andrew are 20
Daniel =1+1.5×20
=1+30=31
Total = 31+10=
41
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