Asked by prisca
1500kg motor car was travelling at 36m\s comes to rest over a distance of 40m.calculate. {a}retardation. {b}an average force that brings the car to rest
Answers
Answered by
Damon
v = Vi + a t
0 = 36 + a t
t = -36/a
d = Vi t + .5 a t^2
40 = 36 (-36/a) + .5 (a)(36^2/a^2)
40 = - 36^2/a + .5 *36^2/a
80 a = -36^2
a = -16.2 m/s^2
then F = m a
= -1500(16.2) Newtons
0 = 36 + a t
t = -36/a
d = Vi t + .5 a t^2
40 = 36 (-36/a) + .5 (a)(36^2/a^2)
40 = - 36^2/a + .5 *36^2/a
80 a = -36^2
a = -16.2 m/s^2
then F = m a
= -1500(16.2) Newtons
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.