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Asked by nan

Find the specific solution of the differential equation dy/dx = 4y/x^2 with condition y(−4) = e.

y equals negative 1 minus 4 divided by x
y equals negative 1 times e raised to the 1 over x power
y equals e raised to the negative 4 over x power
None of these
9 years ago

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Answered by Steve
dy/dx = 4y/x^2
dy/y = 4/x^2 dx
lny = -4/x + c
y = c e^(-4/x)

Now use the condition to find c
9 years ago
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