Asked by John
Find the specific solution of the differential equation dy/dx= 4y/x^2 with condition y(-4) = e.
Answers
Answered by
Steve
dy/dx= 4y/x^2
dy/y = 4/x^2 dx
lny = -4/x +c
y = c e^(-4/x)
c e^(-4/-4) = c*e = e
So, c=1
y = e^(-4/x)
dy/y = 4/x^2 dx
lny = -4/x +c
y = c e^(-4/x)
c e^(-4/-4) = c*e = e
So, c=1
y = e^(-4/x)
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