Asked by Georgette
The length of a rectangular piece of steel in a bridge is 5 meters less than double the width. The perimeter of the piece of steel is 38 meters. Find the length of the piece of steel. Find the width of the piece of steel.
Answers
Answered by
Emiry
L = 2W - 5
P = 38 = 2L + 2W
Now we have 2 equations we can solve for each variable.
2L + 2W = 38
2(2W-5) + 2(W) = 38
4W-10+2W = 38
6W = 48
W = 8
L = 2W-5
L = 2(8)-5 = 11
Width - 8m
Length - 11m
P = 38 = 2L + 2W
Now we have 2 equations we can solve for each variable.
2L + 2W = 38
2(2W-5) + 2(W) = 38
4W-10+2W = 38
6W = 48
W = 8
L = 2W-5
L = 2(8)-5 = 11
Width - 8m
Length - 11m
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.