Asked by sam
Consider the system shown in the diagram. The pulley is a uniform cylinder with mass m3 = 0.60 kg and radius R = 4.0 cm, the other two masses are m1 = 2.5 kg and m2 = 1.0 kg, and á = 30o. Assume the rope is massless, there is no slipping of the rope on the pulley, and there is no friction between m1 and the incline.
(a) What is the acceleration of m1 and m2 (both magnitude and direction)? What is the angular acceleration of the pulley? What are the tensions in the rope (both to the left of the pulley and to the right of the pulley?
(a) What is the acceleration of m1 and m2 (both magnitude and direction)? What is the angular acceleration of the pulley? What are the tensions in the rope (both to the left of the pulley and to the right of the pulley?
Answers
Answered by
Damon
If you tried to copy and paste a picture, that does not work.
Answered by
Chanz
If what I'm thinking it looks like is true a force of 12.25 N is pulling the 9.8 N up for an acc of 0.7. That net 2.45 force causes a torque of .098 on the pulley. I think (better look it up) I = 1/2mr^2 for a solid cylinder, so alpha = tau over I. Do an FBD on the hanging box for tension.
Bob? Damon? am I talking out my butt here?
Bob? Damon? am I talking out my butt here?