Asked by Crystal
Evaluate the sum
∑3 =0 (-1)k × 2k-1/2k-1
6
∑3 =0 (-1)k × 2k-1/2k-1
6
Answers
Answered by
Steve
surely (2k-1)/(2k-1) = 1
So, the sum is
6
∑ (-1)^k = (-1)^3 + (-1)^4 + (-1)^5 + (-1)^6 = -1+1-1+1 = 0
3
So, the sum is
6
∑ (-1)^k = (-1)^3 + (-1)^4 + (-1)^5 + (-1)^6 = -1+1-1+1 = 0
3
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