Asked by Anonymous
I have no idea where to even start.
Suppose heights of men are normally distributed with a mean 69.0 inches and standard deviation 2.8 inches. How many of a group of 1000 men would you expect to be between 70 and 72 inches tall? Round to the nearest whole number.
Suppose heights of men are normally distributed with a mean 69.0 inches and standard deviation 2.8 inches. For groups of 100 men, what would be the usual range of values for the mean height of these groups? Round the mean and standard deviation you use to the nearest tenth.
Suppose heights of men are normally distributed with a mean 69.0 inches and standard deviation 2.8 inches. A particular club has decided they will only allow the tallest 12% of men into their club. What is the shortest height that will be allowed in the club? Round to the nearest tenth of an inch.
Suppose heights of men are normally distributed with a mean 69.0 inches and standard deviation 2.8 inches. How many of a group of 1000 men would you expect to be between 70 and 72 inches tall? Round to the nearest whole number.
Suppose heights of men are normally distributed with a mean 69.0 inches and standard deviation 2.8 inches. For groups of 100 men, what would be the usual range of values for the mean height of these groups? Round the mean and standard deviation you use to the nearest tenth.
Suppose heights of men are normally distributed with a mean 69.0 inches and standard deviation 2.8 inches. A particular club has decided they will only allow the tallest 12% of men into their club. What is the shortest height that will be allowed in the club? Round to the nearest tenth of an inch.
Answers
Answered by
PsyDAG
Z = (score-mean)SD
Look up Z scores to get probability. Multiply by 1000.
DK second.
Third problem use table for .12 to find Z score. Insert Z value in equation above.
Look up Z scores to get probability. Multiply by 1000.
DK second.
Third problem use table for .12 to find Z score. Insert Z value in equation above.
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