I have no idea on how to get started.

If you do not consider air resistance, gravity causes a falling object to descend a distance of (9.8)t2 where t is the time in seconds. If a 16 pound bowling ball is dropped from the tallest building in the world, how many meters does it fall during the 4th and 5th seconds combined.
Thank you

3 answers

distance = 9.8t^2

when t=5
distance = 9.8(25) = 245 m
when t=4
distance = 9.8(16) = 156.8

so in the time from 4 seconds to 5 seconds it fell
245-156.8 or 88.2 m

since we are ignoring air resistance, the fact that the ball has a weight of 16 lbs is irrelevant.
what about during the 4th second?

"how many meters does it fall during the 4th and 5th seconds combined"
I saw that Steve.
It did not seem to make a lot of sense to find the total distance of the 4th and 5th second distances.
So I assumed there was a typo and that the question followed the more traditional wording of that type.