distance = 9.8t^2
when t=5
distance = 9.8(25) = 245 m
when t=4
distance = 9.8(16) = 156.8
so in the time from 4 seconds to 5 seconds it fell
245-156.8 or 88.2 m
since we are ignoring air resistance, the fact that the ball has a weight of 16 lbs is irrelevant.
I have no idea on how to get started.
If you do not consider air resistance, gravity causes a falling object to descend a distance of (9.8)t2 where t is the time in seconds. If a 16 pound bowling ball is dropped from the tallest building in the world, how many meters does it fall during the 4th and 5th seconds combined.
Thank you
3 answers
what about during the 4th second?
"how many meters does it fall during the 4th and 5th seconds combined"
"how many meters does it fall during the 4th and 5th seconds combined"
I saw that Steve.
It did not seem to make a lot of sense to find the total distance of the 4th and 5th second distances.
So I assumed there was a typo and that the question followed the more traditional wording of that type.
It did not seem to make a lot of sense to find the total distance of the 4th and 5th second distances.
So I assumed there was a typo and that the question followed the more traditional wording of that type.