Asked by Andrew
Log base 5 of 16 cubed. Times log base 11 of 6 squared. Equals logx.
Answers
Answered by
bobpursley
logx=log5(16^3)log11(6)^2
logx=6log5(16)log11(6)
I don't know what your question is, nor do I know the base of the logx.
logx=6log5(16)log11(6)
I don't know what your question is, nor do I know the base of the logx.
Answered by
Reiny
(log<sub>5</sub> 16^3 )(log<sub>11</sub> 6^2 = log x
3(log16/log5)(2)(log6/log11) = logx
6(log16/log5)(log6/log11)
6(1.28724...) = logx
7.72346...
x = 10^7.72346..
x = appr 52,900,679
I was using the log properties:
log a^n = n loga , and
log <sub>a</sub> b = logb/loga
3(log16/log5)(2)(log6/log11) = logx
6(log16/log5)(log6/log11)
6(1.28724...) = logx
7.72346...
x = 10^7.72346..
x = appr 52,900,679
I was using the log properties:
log a^n = n loga , and
log <sub>a</sub> b = logb/loga
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