Asked by katy
a box containing 2.00m cubed of air is sealed at sea level pressure of 1.0 atm and a temperature of 20.0 degrees celsius. if the box is heated in an oven to a temperature of 250 degrees celsius, what is the final pressure in atm in the box?
Answers
Answered by
Jai
assuming the air is ideal, we can use the formula,
P1/T1 = P2/T2
where
P1 = initial pressure
P2 = final pressure
T1 = initial temperature (in Kelvin)
T2 = final temperature (in Kelvin)
we first convert the given temp to Kelvin:
T1 = 20 + 273.15 = 293.15 K
T2 = 250 + 273.15 = 523.15 K
substituting,
P1/T1 = P2/T2
1/293.15 = (P2)/523.15
P2 = 523.15/293.15
P2 = 1.79 atm
hope this helps~ :)
P1/T1 = P2/T2
where
P1 = initial pressure
P2 = final pressure
T1 = initial temperature (in Kelvin)
T2 = final temperature (in Kelvin)
we first convert the given temp to Kelvin:
T1 = 20 + 273.15 = 293.15 K
T2 = 250 + 273.15 = 523.15 K
substituting,
P1/T1 = P2/T2
1/293.15 = (P2)/523.15
P2 = 523.15/293.15
P2 = 1.79 atm
hope this helps~ :)
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