Find the average value of f(x) = 1 over x over the interval [e, 2e].

Question

the natural logarithm of 2 over e
negative 1 over 2 times e squared
Ln2 <- my anser
Ln3

Answer 1

avg value is ∫[a,b]f(x)/(b-a)
= lnx[e,2e] / (2e-e)
= (ln(2e)-lne)/e
= (ln2+lne-lne)/e
= ln2/e

you forgot to divide by the interval width