Asked by alex
two lighthouses are situated such that B is 7 km directly east of lighthouse A. A ship at point P observes that A is due north and that the bearing of B is 46°10'. How far is the ship from A and B ?
Answers
Answered by
Reiny
According to my sketch:
tan46°10' = 7/AP
AP = 7/ tan46°10' = ....
sin46°10' = 7/BP
BP = 7/sin46°10' = ....
tan46°10' = 7/AP
AP = 7/ tan46°10' = ....
sin46°10' = 7/BP
BP = 7/sin46°10' = ....
Answered by
alex
how do you sketch this kind of problem?, that's the reason why i'm having trouble with this ..
Answered by
Steve
first thing, of course, is to draw line AB. B is east of A, so it's horizontal.
A is due north of P, so draw a line south from A and put P somewhere on it.
You can estimate angles, at least to some degree :-) so make PB at about 45 degrees.
A is due north of P, so draw a line south from A and put P somewhere on it.
You can estimate angles, at least to some degree :-) so make PB at about 45 degrees.
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