Question
a first order reaction 50% complets in 20 min.how much time will be required for 90% completion?
Answers
DrBob222
Use the two equations below.
k = 0.693/t<sub>1/2</sub>
Then substitute k into the below equation.
ln(No/N) = kt
No = 100
N = 10
k from above.
solve for t in min. Something like 66 minutes.
k = 0.693/t<sub>1/2</sub>
Then substitute k into the below equation.
ln(No/N) = kt
No = 100
N = 10
k from above.
solve for t in min. Something like 66 minutes.