Asked by Maya

You burn 6 grams of carbon in plenty of air:
C ( s) + O2 ( g) = CO2 ( g)
a What volume of gas will form (at rtp)?
b What volume of oxygen will be used up?
Answered by Steve
how many moles involved?

1 mole is 22.4L at stp
Answered by Anonymous
a) mass=6g Ar=12
Mr=12g/mol
n=m÷Mr
n=6g÷12g/mol
n=0.5 mol


V=n*Vm =0.5molx24dm(cubed)/mol
=12dm(cubed)
Answered by ertyhujkjh
57
Answered by ANIME KING
E=MC SQUARE
THE E=MC SQUARE COMES IN DR.STONE ANIME.BUT 12 DM3 IS THERE BECAUSE THERE IS ONLY 6 G OF CARBON . 6 G OF CARBON HAS THE VOLUME OF 12DM3 WHICH IS 24DM3 DIVIDED BY TWO.SO DONT WORRY IF YOU HAVE ANY DOUBT YOU CAN CALL ME.9976852351
Answered by Tav
Please Label which one is A and B
Answered by Sanad
Hi what is a and what is b I don't know.
Answered by Your mom
Go clean the dishes
Answered by kssjggdjgbj
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Answered by Taha-Manz
a) 12grams= 1 mole
6 grams= 0.5 mole
0.5 ×24= 12dm³
Answer=12dm³
Answered by Bot
b) From the balanced equation, we can see that for every 1 mole of carbon burned, 1 mole of oxygen is required. Therefore, since we have 0.5 moles of carbon, we also need 0.5 moles of oxygen.

Using the ideal gas law, we can calculate the volume of oxygen used:

PV = nRT

Assuming constant temperature and pressure (rtp):

V = nRT/P

V = (0.5 mol)(8.31 J/mol·K)(273 K)/(101.3 kPa)

V = 10.9 L or 10900 mL

Therefore, 10.9 L or 10900 mL of oxygen will be used up.