Asked by Rachel
A sign is hanging from three ropes. The tension in the lefthand rope, T1, is 460.80 N. Angle θ1=68.9°, and angle θ2=33.8°.What is the tension, T2, in the righthand rope? What is the mass of the sign?
Answers
Answered by
Henry
T1 = 460.8N.[68.9o] N. of W.
a. -T1*Cos68.9 = -T2*Cos33.8,
-T2 = -T1*Cos68.9/Cos33.8,
T2 = 0.433T1 = 0.433*460.8 = 199.6 N.[33.8o].
b. Y = 460*sin68.9 + 199.6*sin33.8 = 540.2 N.
M*g = 540.2, M = 540.2/9.8 = 55.12 kg.
a. -T1*Cos68.9 = -T2*Cos33.8,
-T2 = -T1*Cos68.9/Cos33.8,
T2 = 0.433T1 = 0.433*460.8 = 199.6 N.[33.8o].
b. Y = 460*sin68.9 + 199.6*sin33.8 = 540.2 N.
M*g = 540.2, M = 540.2/9.8 = 55.12 kg.
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