I guess it starts at 0 height
h = a x^2 + b x
148 = a (1)^2 + b(1)
272 = a(2)^2 + b(2)
b = 148 - a
272 = 4 a + 2 (148-a)
272 = 4 a -2 a + 296
2 a = -24
a = -12 (should be 16 on earth but anyway)
b = 148 +12 = 160
so
h = -12 x^2 + 160 x
if x = 6
h = -12*36 + 160(6) = 528
A ball is launched from a slingshot. Its height, h(x), can be represented by a quadratic function in terms of time, x, in seconds.
After 1 second, the ball is 148 feet in the air, after 2 seconds the ball is 272 feet in the air.
Find the height in feet of the ball after 6 seconds in the air?
1 answer
1 answer