Asked by Maryanne
A ball is launched to the right with a horizontal velocity of 16 m/s from the top of a pillar that is 50 m high. How long will it be in the air? How far will it land from the base of the pillar
Answers
Answered by
R_scott
flight time (t) ... 50 = 1/2 * g * t^2 ... 100 / 9.8 = t^2
distance from base ... 16 m/s * t = ?
distance from base ... 16 m/s * t = ?
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