Asked by Maryanne

A ball is launched to the right with a horizontal velocity of 16 m/s from the top of a pillar that is 50 m high. How long will it be in the air? How far will it land from the base of the pillar
Answered by R_scott
flight time (t) ... 50 = 1/2 * g * t^2 ... 100 / 9.8 = t^2

distance from base ... 16 m/s * t = ?