Question
a place kicker kicks a football with a velocity of 20.0 minutes per hour and at an angle at 53 degrees
a.how long is the ball in the air
b.how far away does it land
c.how high does it travel
a.how long is the ball in the air
b.how far away does it land
c.how high does it travel
Answers
Henry
20 minutes per hour makes no sense. So let's assume:
Vo = 20m/s[53o].
Xo = 20*Cos53 = 12.0 m/s.
Yo = 20*sin53 = 16.0 m/s.
a. Y = Yo + g*Tr = 0, 16 - 9.8*Tr = 0, -9.8Tr = -16, Tr = 1.63 s. = Rise time.
Tf = Tr = 1.63 s. = Fall time.
T = Tr+Tf = 1.63 + 1.63 = 3.27 s. = Time in air.
b. d = Xo*T = 12 * 3.27 = 39.2 m.
c. Y^2 = Yo^2 + 2g*h. Y = 0, Yo = 16 m/s, g = -9.8 m/s^2, h = ?.
Vo = 20m/s[53o].
Xo = 20*Cos53 = 12.0 m/s.
Yo = 20*sin53 = 16.0 m/s.
a. Y = Yo + g*Tr = 0, 16 - 9.8*Tr = 0, -9.8Tr = -16, Tr = 1.63 s. = Rise time.
Tf = Tr = 1.63 s. = Fall time.
T = Tr+Tf = 1.63 + 1.63 = 3.27 s. = Time in air.
b. d = Xo*T = 12 * 3.27 = 39.2 m.
c. Y^2 = Yo^2 + 2g*h. Y = 0, Yo = 16 m/s, g = -9.8 m/s^2, h = ?.