x = (-√2 ± √(2 - 4(1)(1/2)) )/2
= - √2/2
ahh, then it must have factored
sure enough
(x + √2/2)^2 = 0
x = -√2/2
no need for complex numbers, the root is real.
x^2+√2x+1/2=0
Solve using the quadratic formula and use complex numbers.
3 answers
Thank u very much, I was also confused cause I didn't understand why we needed complex numbers :)
√2xsquare-3/√2x+1/√2=0
A=√2
B=-3/√2
C=1/√2
-b+-√bsquare -4ac/2a
(-3/√2)+-√(-3/√2) square-4.√2.1/√2 /2√2
A=√2
B=-3/√2
C=1/√2
-b+-√bsquare -4ac/2a
(-3/√2)+-√(-3/√2) square-4.√2.1/√2 /2√2
1 answer