Asked by John
An elementary student kicks a ball straight into the air with a velocity of 16 feet/sec. If acceleration due to gravity is -32 ft/sec^2, how many seconds after it leaves his foot will it take the ball to reach its highest point? Assume the position at time t = 0 is 0 feet.
Answers
Answered by
Steve
the height h is
h = 16t - 32t^2
as with any parabola, the vertex is at t = -b/2a = -16/-64 = 1/4 second
h = 16t - 32t^2
as with any parabola, the vertex is at t = -b/2a = -16/-64 = 1/4 second
Answered by
John
Are you sure that's how you would do that? Because its not one of my options. my options are 1.25, 6, 0.50 or cannot be determined.
Answered by
Steve
h = 16t(1-2t)
The roots are 0 and 1/2. The vertex lies halfway between the roots, at t = 1/4.
The roots are 0 and 1/2. The vertex lies halfway between the roots, at t = 1/4.